Solve the following equations :-
$3 x - y = 7; x + 4 y = 11$

Open in App

Solution

$\begin{matrix} 3 x - y = 7 - - - (1) x + 4 y = 44 - - - (2) m u l t i p l y e q u a t i o n (2) b y 3 t h e (2) - (1) 3 x + 12 y = 132 3 x - y = 7 - - - - - - - - 0 + 13 y = 125 ∴ y = \frac{125}{13} N o w x = \frac{7 + y}{3} = \frac{7 + \frac{125}{13}}{3} = \frac{91 + 125}{13 (3)} = \frac{216}{39} H e n c e, x = \frac{216}{39} a n d y = \frac{125}{13} . \end{matrix}$

Suggest Corrections

Similar questions

-

Solve the following systems of equations:

$3 x - \frac{y + 7}{11} + 2 = 10$

$2 y + \frac{x + 11}{7} = 10$

Solve the following pair of equations by elimination method.

3 x - \frac{y + 7}{11} + 2 = 10

2 y + \frac{x + 11}{7} = 10

\frac{x + 11}{7} + 2 y = 10, 3 x = 8 + \frac{y + 7}{11}

Join BYJU'S Learning Program