Question

Solve the following equations by trial-and-error method.

$x+18=24$

Answer 1

Solving the given equatio:

We substitute different values of $x$ and we pick up the value of $x$ for which the left hand side (L.H.S.) of given equation is eqaul to right hand side (R.H.S.), this method is called trial-and-error method.

we put, $x$$=5$ in given equation ,

then L.H.S.$=$$5+18$ $=$ $23$$\ne$$24$

$\Rightarrow$ $x$$=5$ is not a solution.

Now, we put $x$$=6$,

then we get L.H.S.$=$ $6+18=$$24$$=$$24$

Therefor, L.H.S $=$ R.H.S.

Hence, solution of the given equation is $x$$=6$.