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Two Point Form of a Line

Solve the fol...

Question

Solve the following equations.
$l o g_{2} s i n x + l o g_{1 / 2} (- c o s x) = 0.$

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Solution

sinx must be positive and cosx must be negative

impies x belongs to second quadrant

it can be written as

${log}_{2} s i n x - {log}_{2} (- c o s x)$

= ${log}_{2} (- t a n x)$ =0

implies $t a n x = - 1$

$∴$ $x = 135^{0}$

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