CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Two Point Form of a Line

Solve the fol...

Question

Solve the following equations.
$l o g_{2} s i n x + l o g_{1 / 2} (- c o s x) = 0.$

Open in App

Solution

sinx must be positive and cosx must be negative

impies x belongs to second quadrant

it can be written as

${log}_{2} s i n x - {log}_{2} (- c o s x)$

= ${log}_{2} (- t a n x)$ =0

implies $t a n x = - 1$

$∴$ $x = 135^{0}$

Suggest Corrections

thumbs-up

0

Similar questions

Q. Solve the following equation:

{log}_{\frac{1}{3}} x - 3 \sqrt{{log}_{\frac{1}{3}} x} + 2 = 0

Q. Solve the following equation:

cos x + sec x = 2

Q. Solve the following equations.

l o g_{2} s i n x - l o g_{2} c o s x - l o g_{2} (1 - t a n x) - l o g_{2} (1 + t a n x) = 1.

Q. Solve the following inequality:

{log}_{2} (sin \frac{x}{2}) < - 1

Q. Solve the following equations

cos x - cos 2 x + cos 3 x = 0

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Straight Line

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Two Point Form of a Line

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon