Solve the following for x :
12a+b+2x=12a+1b+12x
The given equation is 12a+b+2x=12a+1b+12x
12a+b+2x=12a+1b+12x⇒12a+b+2x−12x=12a+1b⇒2x−2a−b−2x2x(2a+b+2x)=b+2a2ab⇒−2a−b2x(2a+b+2x)=b+2a2ab⇒−(2a+b)2x(2a+b+2x)=b+2a2ab⇒−1x(2a+b+2x)=1ab⇒2x2+2ax+bx+ab=0⇒2x(x+a)+b(x+a)=0⇒(x+a)(2x+b)=0⇒x+a=0or2x+b=0⇒x=−a, or x=−b2