Question 69
Solve the following:
2y−34−3y−52=y+34
Given, 2y−34−3y−52=y+34⇒2y−3−2(3y−5)4=4y+34⇒2y−3−6y+10=4y+3⇒−4y+7=4y+3⇒−8y=−4⇒−8y−8=−4−8∴y=12
Question 55
y−(4−3y)2y−(3+4y)=15