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Fundamental Theorem of Arithmetic

Question 72 S...

Question

Question 72

Solve the following:

$\frac{3 x + 2}{2 x - 3} = - \frac{3}{4}$

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Solution

Given, $\frac{3 x + 2}{2 x - 3} = - \frac{3}{4} \Rightarrow 4 (3 x + 2) = - 3 (2 x - 3) \Rightarrow 12 x + 8 = - 6 x + 9 \Rightarrow 12 x + 6 x = 9 - 8 \Rightarrow 18 x = 1 \Rightarrow \frac{18 x}{18} = \frac{1}{18} ∴ x = \frac{1}{18}$

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Question 65

Solve the following:

$\frac{2 x - 1}{5} = \frac{3 x + 1}{3}$

\frac{3 x - 2}{4} - \frac{2 x + 3}{3} = \frac{2}{3} - x

2 + \frac{2 x - 3}{2 x + 3} = \frac{3 x + 4}{x + 2}

Q. Solve the equations:

\frac{3 x^{4} + x^{2} - 2 x - 3}{3 x^{4} - x^{2} + 2 x + 3} = \frac{5 x^{4} + 2 x^{2} - 7 x + 3}{5 x^{4} - 2 x^{2} + 7 x - 3}

Solve the following:

lim x \to \infty {(\frac{3 x - 4}{3 x + 2})}^{\frac{x + 1}{3}}

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Fundamental Theorem of Arithmetic

Standard X Mathematics

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