Question 72 Solve the following-3 x-2-2 x-3-3-4

Given, 3x+2/2x 3= 3/4 ⇒ 4(3x+2)= 3(2x 3) ⇒ 12x+8= 6x+9 ⇒ 12x+6x=9 8 ⇒ 18x=1 ⇒18x/18=1/18 ∴ x=1/18 ...

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Fundamental Theorem of Arithmetic

Question 72 S...

Question

Question 72

Solve the following:

$\frac{3 x + 2}{2 x - 3} = - \frac{3}{4}$

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Question 65

Solve the following:

$\frac{2 x - 1}{5} = \frac{3 x + 1}{3}$

\frac{3 x - 2}{4} - \frac{2 x + 3}{3} = \frac{2}{3} - x

2 + \frac{2 x - 3}{2 x + 3} = \frac{3 x + 4}{x + 2}

\frac{3 x^{4} + x^{2} - 2 x - 3}{3 x^{4} - x^{2} + 2 x + 3} = \frac{5 x^{4} + 2 x^{2} - 7 x + 3}{5 x^{4} - 2 x^{2} + 7 x - 3}

lim x \to \infty {(\frac{3 x - 4}{3 x + 2})}^{\frac{x + 1}{3}}

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