Question 55
Solve the following:
y−(4−3y)2y−(3+4y)=15
Given, y−(4−3y)2y−(3+4y)=15⇒5(y−4+3y)=2y−3−4y⇒5(4y−4)=−3−2y⇒20y−20=−3−2y⇒20y+2y=20−3⇒22y=17⇒22y22=1722∴y=1722
Question 69
2y−34−3y−52=y+34