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Question

Solve the following inequality:
0.5x+4910x2+x2<12

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Solution

0.5x+4910x2+x2<12
x+9810x2x+22(10x2+5x4x2)<0
10x2+100(5x2)(2x+1)<0
x210(5x2)(2x+1)>0
(x3.16)(x+3.16)(5x2)(2x+1)>0
x(,3.16)(0.5,25)(3.16,)

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