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Question

Solve the following inequality:
loglog2(0.5x)(x210x+22)>0

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Solution

log(x210x+22)loglog0.5xloglog2>0Hence,Forlog(x210x+22)x210x+22>0x(,53)(5+3,)Also,Forlog2(0.5x)log2(0.5x)>0log(0.5x)>00.5x>1x>2
Taking intersection, we get x(5+3,)
For (5+3,)loglog2(0.5x)>0
Hence, For x(5+3,)
log(x210x+22)>0x210x+22>1x210x+21>0(x3)(x7)>0x(,3)(7,)
Hence, x(7,)

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