Solve the following inequation, write the solution set and represent it on the number line: −x3≤x2−113<16,x∈R.
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Solution
Given: −x3≤x2−113<16 Taking L.C.M. of 3,2 and 6 is 6. −x3×6≤x2×6−43×6<16×6 −2x≤3x−8<1 ⇒−2x≤3x−8 and 3x−8<1 ⇒8≤3x+2x⇒3x<1+8 ⇒8≤5x⇒3x<9 ⇒85≤x⇒x<3 ∴ The solution set is {x:1.6≤x≤3,xϵR}