Question

Solve the following:

$\left(\frac{0.5y-2}{1.2y+4}\right)=\frac{-7}{5}$

Answer 1

Here, we have to solve

$\left(\frac{0.5y-2}{1.2y+4}\right)=\frac{-7}{5}$

By cross multiplying

$\begin{array}{rcl}& \Rightarrow & 5(0.5y-2)=-7(1.2y+4)\\ & \Rightarrow & 2.5y-10=-8.4y-28\\ & \Rightarrow & 2.5y+8.4y=-28+10\\ & \Rightarrow & 10.9y=-18\\ & \Rightarrow & y=\frac{-18}{10.9}\\ or,y& =& \frac{-18\times 10}{10.9\times 10}\\ y& =& \frac{-180}{109}\end{array}$