wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve the following linear equation:

x2-15=x3+14


Open in App
Solution

Compute the required value:

x2-15=x3+14

On taking LCM on both sides and on solving, we get

5x-210=4x+31212(5x-2)=10(4x+3)60x-24=40x+3060x-40x=30+2420x=54x=5420x=2710

Hence, x=2710 is the solution of given equation.


flag
Suggest Corrections
thumbs-up
775
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon