Solve the following linear equation:
x2-15=x3+14
Compute the required value:
On taking LCM on both sides and on solving, we get
5x-210=4x+312⇒12(5x-2)=10(4x+3)⇒60x-24=40x+30⇒60x-40x=30+24⇒20x=54⇒x=5420⇒x=2710
Hence, x=2710 is the solution of given equation.
Determine whether the following numbers are in proportion or not:
13,14,16,17
Solve for x:x−23=2x7
loge(n+1)−loge(n−1)=4a[(1n)+(13n3)+(15n5)+...∞] Find 8a.