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Question

Solve the following pair of equations.

5x1+1y2=2

6x13y2=1

Here, x 1 and y 2


A

x = 4, y = 5

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B

x = 5, y = 3

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C

x=13, y=13

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D

x = 7, y = 11

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Solution

The correct option is A

x = 4, y = 5


If we substitute 1x1 as p and 1y2 as q in the given equations, we get the equations as

5p+q=2 .......(1)

6q3q=1 .......(2)

Now, we can solve the pair of equations by method of elimination.

On multiplying the first equation by 3 and then adding it to (2), we get

15p+3q=6

6p3q=1

_____________

p=13

Now by substituting the value of p in equation (2) we get
q=13

Now, p=1x1

1x1=13

x=4

Similarly we assumed q=1y2

1y2=13

y2=3

y=5

x=4 and y=5


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