CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

Solve the following pair of equations.

5x1+1y2=2

6x13y2=1

Here, x 1 and y  2


  1. x = 4, y = 5

  2. x = 5, y = 3

  3. x=13, y=13

  4. x = 7, y = 11


Solution

The correct option is A

x = 4, y = 5


 If we substitute   1x1 as p and  1y2 as q in the given equations, we get the equations as

5p+q=2   .......(1)

6q3q=1   .......(2)

Now, we can solve the pair of equations by method of elimination.

On multiplying the first equation by 3 and then adding it to (2), we get

15p+3q=6

  6p3q=1

_____________

        p=13

Now by substituting the value of p in equation (2) we get
q=13

Now, p=1x1

1x1=13

x=4

Similarly we assumed q=1y2

1y2=13

y2=3

y=5

x=4 and y=5

flag
 Suggest corrections
thumbs-up
 
0 Upvotes


Similar questions
View More...



footer-image