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Question

Question 3
Solve the following pair of linear equations by the substitution and cross-multiplication methods:
8x +5y = 9
3x +2y = 4

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Solution

8x +5y = 9 ... (i)
3x +2y = 4 ... (ii)
From equation (ii), we get
x=42y3 ... (iii)
Putting this value in equation (i), we get
8×42y3+5y=9
32 - 16y +15y = 27
-y = -5
y = 5 ... (iv)
Substituting this value in equation (ii), we get
3x + 10 = 4
x = -2
Hence, x = -2, y = 5
By cross multiplication again, we get
8x + 5y -9 = 0
3x + 2y - 4 = 0
x20(18)=y27(32)=11615
x2=y5=11
x2=1 and y5=1
x=2 and y=5

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