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Question

Solve the following pair of linear equations by the substitution method.
0.2x + 0.3y = 1.3; 0.4x + 0.5y = 2.3


A

x = 2, y = 3

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B

x = 2, y = -2

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C

x = 1, y = -3

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D

x = -2, y = -1

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Solution

The correct option is A

x = 2, y = 3


0.2x + 0.3y = 1.3 ... (i)
0.4x + 0.5y = 2.3 ... (ii)
0.2x + 0.3y = 1.3
From equation (i), we get
0.2x = 1.3 - 0.3y
Dividing by 0.2, we get
x=1.30.20.30.2y
x = 6.5 - 1.5 y …(iii)
Substituting the value of x in equation (ii), we get,
0.4x + 0.5y = 2.3
0.4 × (6.5 - 1.5y) + 0.5y = 2.3
2.6 - 0.6y + 0.5y = 2.3
-0.1y = 2.3 - 2.6
y=0.30.1
y = 3
Substituting the value in equation (iii) we get,
x = 6.5 - 1.5 y
x = 6.5 - 1.5(3)
x = 6.5 - 4.5
x = 2
x = 2 and y = 3


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