Solve the following pair of linear equations by the substitution method.
0.2x + 0.3y = 1.3; 0.4x + 0.5y = 2.3
x = 2, y = 3
0.2x + 0.3y = 1.3 ... (i)
0.4x + 0.5y = 2.3 ... (ii)
0.2x + 0.3y = 1.3
From equation (i), we get
0.2x = 1.3 - 0.3y
Dividing by 0.2, we get
x=1.30.2−0.30.2y
x = 6.5 - 1.5 y …(iii)
Substituting the value of x in equation (ii), we get,
⇒ 0.4x + 0.5y = 2.3
⇒ 0.4 × (6.5 - 1.5y) + 0.5y = 2.3
⇒ 2.6 - 0.6y + 0.5y = 2.3
⇒ -0.1y = 2.3 - 2.6
⇒ y=−0.3−0.1
⇒ y = 3
Substituting the value in equation (iii) we get,
⇒ x = 6.5 - 1.5 y
⇒ x = 6.5 - 1.5(3)
⇒ x = 6.5 - 4.5
⇒ x = 2
∴ x = 2 and y = 3