wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve the following pair of linear equations:
x2+2y3=1 and xy3=3

A
2,-3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
-3,2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
4,-3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2,4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 2,-3
Given,
x2+2y3=1 and xy3=3
By taking the LCM of the equations we get ,
3x + 4y = -6.... (1)
and 3x - y = 9..... (2)
(1) - (2) gives
3x + 4y - 3x + y = -6 - 9
5y = -15 y = -3

Substituting y = -3 in (1)
3x + 4(-3) = -6
3x - 12= -6
3x = 6 x = 2

x = 2 and y = -3

flag
Suggest Corrections
thumbs-up
442
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Discriminant
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon