Question

Solve the following pair of linear (simultaneous) equations by the method of elimination:

$6x=7y+7$
$7y-x=8$

• A. $x=3,y=\frac{11}{7}$
• B. $x=2,y=\frac{1}{2}$
• C. $x=6,y=\frac{13}{5}$
• D. $x=4,y=\frac{-1}{2}$

Answer 1

The correct option is A $x=3,y=\frac{11}{7}$

$6x-7y=7$ ...$\left(1\right)$

$-x+7y=8$ ...$\left(2\right)$

Adding $\left(1\right)$ and $\left(2\right)$,

$5x=15$

$x=3$

Substituting $x=3$ in $\left(1\right)$, we get

$18-7y=7$

$7y=11$

$y=\frac{11}{7}$

So, $x=3,y=\frac{11}{7}$

Option $A$