Solve the following pair of simultaneous equations:
$a = b + 2$
$2 a - b = 7$

a = - 2, b = 9

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a = 12, b = 6

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a = - 3, b = 7

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a = 5, b = 3

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Solution

The correct option is B $a = 5, b = 3$
$a - b = 2$ ...(1)
$2 a - b = 7$ ...(2)
Subtract eq(2) from eq(1) we get
$a = 5 a n d b = 3$

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Q. Question 12

Product of

6 a^{2} - 7 b + 5 a b

and

2 a b

is
a)

12 a^{3} b - 14 a b^{2} + 10 a b

12 a^{3} b - 14 a b^{2} + 10 a^{2} b^{2}

6 a^{2} - 7 b + 7 a b

12 a^{2} b - 7 a b^{2} + 10 a b

If
A = {1, 2, 3, 4}

B = {3, 4, 5, 6, 7}

C = {6, 7, 8, 9}

D = {7, 8, 9, 10}

$\begin{matrix} C o l u m n A & C o l u m n B 1. A \cup B & a . {3, 4, 6, 7} 2. A \cap B & b . \emptyset 3. (B \cap C) \cup D & c . {3, 4} 4. B \cup C \cup D & d . {3, 4, 5, 6, 7, 8, 9, 10} 5. (A \cap B) \cap (B \cup C) & e . {1, 2, 3, 4, 5, 6, 7} f . {6, 7, 8, 9, 10} g . {7} \end{matrix}$

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Solve the following pair of simultaneous equations:a=b+22a−b=7

The correct option is B a=5,b=3a−b=2 ...(1)2a−b=7 ...(2)Subtract eq(2) from eq(1) we get a=5andb=3

Solve the following pair of simultaneous equations:
$a = b + 2$
$2 a - b = 7$

The correct option is B $a = 5, b = 3$
$a - b = 2$ ...(1)
$2 a - b = 7$ ...(2)
Subtract eq(2) from eq(1) we get
$a = 5 a n d b = 3$