Solve the following pairs of linear equations using the method of elimination by substitution

1) .2x-3y+6=0. 2x+3y-18=0

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Solution

2x-3y+6=0
X=(-6+3y) /2
Put this value in another equation

2x+3y-18=0
2(-6+3y )/2 +3y-18=0
-6+3y+3y-18=0
6y-24=0
6y=24
y=4
Put value of y in any of these equation
Say 1st
2x-3×4+6=0
2x-12+6=0
2x-6=0
2x=6
x=3

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Similar questions

Solve the following pairs of linear (simultaneous) equations using method of elimination by substitution:

$2 x - 3 y + 6 = 0$

$2 x + 3 y - 18 = 0$

2 x + 3 y = 8

2 x = 2 + 3 y

2 x + 3 y = 8

2 x = 2 + 3 y

x + y = 5

2 x - 3 y = 4

0.2 x + 0.1 y = 25

2 (x - 2) - 1.6 y = 116

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