Solve the following pairs of linear (simultaneous) equations using method of elimination by substitution:

$y = 4 x - 7$

$16 x - 5 y = 25$

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Solution

y = 4x -7...(1)

16x- 5y = 25...(2)

From (1), y = 4x - 7

Putting this value of y in (2)

16x - 5 (4x - 7) = 25

16x - 20x + 35 = 25

-4x = -10

x=5/2

From (1)

y=4[5/2]-7

y = 10-7=3

The solution is x=5/2 and y=3

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Solve the following pairs of linear (simultaneous) equations using method of elimination by substitution:

$2 x + 7 y = 39$

$3 x + 5 y = 31$

y = 4 x - 7

16 x - 5 y = 25

y = 4 x - 7

16 x - 5 y = 25

2 x + 7 y = 39

3 x + 5 y = 31

8 x + 5 y = 9

3 x + 2 y = 4

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