22x−3.2x+2+32=0(2x)2−3×2x×22+32=0(2x)2−12×2x+32=0Let a=2xa2−12a+32=0a2−8a−4a+32=0a(a−8)−4(a−8)=0(a−8)(a−4)=0a=8 or a=4
Case (i):
a=8⇒2x=8⇒2x=23⇒x=3
Case (ii):
a=4⇒2x=4⇒2x=22⇒x=2
So x = 3 or 2
Solve each of the following quadratic equations: 22x−3.2(x+2)+32=0