Solve the following quadratic equation:
$48 x^{2} - 13 x - 1 = 0$

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Solution

$48 x^{2} - 13 x - 1 = 0$

$= 48 x^{2} - 16 x + 3 x - 1 = 0$

$= 16 x (3 x - 1) + 1 (3 x - 1) = 0$

$= (3 x - 1) (16 x + 1) = 0$

$3 x - 1 = 0$
$x = 1 / 3$
and
$16 x + 1 = 0$
$x = - 1 / 16$

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