Question

Solve the following quadratic equation by factorisation method.

$3x^2-x-10=0$

Answer 1

$$\begin{gathered} 3x^2–x-10=0 \\ \Rightarrow 3x^2–6x+5x–10=0 \\ \Rightarrow 3x(x–2)+5(x-2)=0 \\ \Rightarrow (3x+5)(x–2)=0 \end{gathered}$$

Either $x=\frac{-5}{3}\text{or}x=2$

Therefore, $\frac{\mathbf{-}\mathbf{5}}{\mathbf{3}}$ and $\mathbf{2}$ are the roots of the given quadratic equation.