Question

Solve the following quadratic equation by factorization method
$x^2-5x-36=0$

Answer 1

$x^2-5x-36=0$
$\therefore x^2-(9-4)x-36=0$
$\therefore x^2-9x+4x-36=0$
$\therefore x(x-9)+4(x-9)=0$
$\therefore (x-9)(x+4)=0$
$\therefore x=9$ or $x=-4$
$\therefore$ The roots of the given equation are $9$ and $-4$.