Question

Solve the following quadratic equation by factorization method
$x^2-5x+6=0$

Answer 1

Given Equation:

$x^2-5x+6=0$

Splitting the middle term, we get

$x^2-3x-2x+6=0$

$\Rightarrow x(x-3)-2(x-3)=0$

$\Rightarrow (x-3)(x-2)$

$\Rightarrow x=2$ or $x=3$