Question

Solve the following quadratic equation by factorization method
$x^2-7x+10=0$

Answer 1

We have,
$x^2-7x+10=0$
$x^2-(5+2)x+10=0$
$x^2-5x-2x+10=0$
$x(x-5)-2(x-5)=0$
$(x-5)(x-2)=0$
$x=5$
or $x=2$