Question

Solve the following quadratic equation by factorization method
$x^2-7x+12=0$

Answer 1

$x^2-7x+12=0$
$\Rightarrow x^2-3x-4x+12=0$
$\Rightarrow x(x-3)-4(x-3)=0$
$\Rightarrow (x-3)(x-4)=0$
$\Rightarrow x=3$ or $x=4$