Solve the following quadratic equation: x2−10x+21=0
A
3
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B
-7
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C
7
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D
-3
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E
3 or 7
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Solution
The correct option is E
3 or 7 Let p and q be the roots of the equation. Then, sum of the roots, p + q = −−101=10 Product of the roots. pq = 21 so, x can be either 3 or 7