Solve the following Quadratic equation:
$x^{2} + 6 x - (a^{2} + 2 a - 8) = 0$ .

Open in App

Solution

Formula for roots of quadratic

expression $a x^{2} + b x + c = 0$ is

$= \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}$

So for $x^{2} + 6 x - (a^{2} + 2 a - 8)$ is

$= \frac{- 6 \pm \sqrt{36 + 4 (a^{2} + 2 a - 8)}}{2}$

$= \frac{- 6}{2} \pm \sqrt{9 - 8 + a^{2} + 2 a}$

$= \frac{- 6}{2} \pm \sqrt{(a + 1)^{2}}$

$= - 3 \pm (a + 1)$

Suggest Corrections

Similar questions

x^{2} + 6 x - (a^{2} + 2 a - 8) = 0

x^{2} + 6 x - 7 = 0

Solve the following quadratic equation for $x$ :

$x^{2} - 2 a x - (4 b^{2} - a^{2}) = 0$

Find the roots of each of the following equations, if they exist, by applying the quadratic formula:
$x^{2} + 6 x - (a^{2} + 2 a - 8) = 0$

x^{2} - 2 a x + a^{2} - b^{2} = 0

Join BYJU'S Learning Program