Solve the following quadratic equations by factorization-2 x x-4-2 x-5 x-3-253

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Solving a Quadratic Equation by Factorization Method

Solve the fol...

Question

Solve the following quadratic equations by factorization:

$\frac{2 x}{x - 4} + \frac{2 x - 5}{x - 3} = \frac{25}{3}$

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Solution

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2 (x + 1)^{2} - 5 (x + 1) = 12

\frac{2 x}{(x - 4)} + \frac{(2 x - 5)}{(x - 3)} = \frac{25}{3}, (x \neq 4, 3)

\frac{2}{x + 1} + \frac{3}{2 (x - 2)} = \frac{23}{5 x}; x \neq 0, - 1, 2

4

Solve the following quadratic equation by factorization.
$\frac{2}{x + 1} + \frac{3}{2 (x - 2)} = \frac{23}{5 x}; x \neq 0, - 1, 2$

x^{2} - 5 x + 4 = 0

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