Question

Solve the following quadratics $x^2-2x+2=0$

Answer 1

$x^2-2x+2=0\text{We will apply discriminant rule,}x=\frac{-b\pm \sqrt{D}}{2a}........\left(A\right)whereD=b^2-4ac=2^2-\mathrm{4.1.2}=4-8=-4from\left(A\right)x=\frac{-2\pm \sqrt{-4}}{2}=\frac{-2\pm 2i}{2}=-1\pm i\therefore x=-1+i-1-i$