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Question

Solve the following quadric equations by factorization method only 4x212x+25=0

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Solution

4x212x+25=0Now, completing the squares, we get(2x3)2+16=0(2x3)24i2=0(2x3+4i)(2x34i)=0(2x3+4i)=0Or (2x34i)=0x=32+2i,322i


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