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Question

Solve the following sets of simultaneous equations.
2x+3y+4=0;x5y=11

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Solution

Given
x5y=11
x=11+5y.......(1)
2x+3y+4=0
substitute value of x from (1) in the above equation, we get
2(11+5y)+3y=4
22+10y+3y=4
10y+3y=422
13y=26
y=2613
y=2
Putting value of y in (1) ,we get
x=11+5y
x=11+5×(2)
x=1110
x=1
Therefore, x=1 and y=2

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