CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve the following simultaneous equations by substitution method.
2x+3y=4;x5y=11

A
x=1,y=2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
x=1,y=2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
x=1,y=2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
x=1,y=2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B x=1,y=2
2x+3y=4..........(1)
x5y=11
x=11+5y .............(2)
Substituting eq. (2) in eq. (1), we get,
2(11+5y)+3y=4
22+10y+3y=4
22+4=13y
y=2613

y=2
Substituting y=2 in (1) we get,
x=1

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Algebraic Solution
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon