Question

Solve the following sets of simultaneous equations.
$2x+3y+4=0;x-5y=11$

Answer 1

Given

$x-5y=11$

$x=11+5y.......\left(1\right)$

$2x+3y+4=0$

substitute value of $x$ from (1) in the above equation, we get

$2(11+5y)+3y=-4$

$22+10y+3y=-4$

$10y+3y=-4-22$

$13y=-26$

$y=\frac{-26}{13}$

$y=-2$

Putting value of $y$ in (1) ,we get

$x=11+5y$

$x=11+5\times (-2)$

$x=11-10$

$x=1$

Therefore, $x=1$ and $y=-2$