Question

Solve the following sets of simultaneous equations.
$2x-7y=7;3x+y=22$

Answer 1

Given

$3x+y=22$

$y=22-3x.......\left(1\right)$

$2x-7y=7$

substitute value of $y$ from (1) in the above equation, we get

$2x-7(22-3x)=7$

$2x-154+21x=7$

$2x+21x=7+154$

$23x=161$

$x=\frac{161}{23}$

$x=7$

Putting value of $x$ in (1) ,we get

$y=22-3x$

$y=22-3\times \left(7\right)$

$y=22-21$

$y=1$

Therefore, $x=7$ and $y=1$