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Question

Solve the following simu1taneous equations.
(1) 5x3y=8; 3x+y=2

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Solution

Consider the equation 3x+y=2
Multiply the quation by 3 so that we can eliminate y
3(3x+y=2)=3×2
9x+3y=6
Adding it with 5x3y=8
9x+3y+5x3y=6+8
14x=14
x=1

Putting the value of x in equation 3x+y=2
3×1+y=2
3+y=2
y=23
y=1

So, we have x=1andy=1


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