Solve the following simultaneous equations by elimination method and find the value of $x$ $3 x - 2 y = 4; 6 x + 7 y = 19$

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Solution

$3 x - 2 y = 4$ ..........(1)
$6 x + 7 y = 19$ .........(2)
Multiply (1) by 2 we get,
$6 x - 4 y = 8$ ..........(3)
Subtracting (2) and (3) we get,
$y = 1$
Re substituting $y = 1$ in (1) we get,
$x = 2$

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