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Question

Solve the following system of equations
2x+3y=9
3x+4y=5

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Solution

The given equations are
2x+3y=9 .........(i)
and 3x+4y=5 ......(ii)
Multiplying equation (i) by 3 and (ii) by 2
6x+9y=27
6x+8y=10
and then subtracting, we get
y=17
Putting the value of y=17 in equation (i), we get
2x+3×17=9
2x+51=9
2x=915
2x=42
x=21
Hence the required solution is x=21 and y=17.

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