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Byju's Answer
Standard XII
Mathematics
Bisectors of Angle between Two Lines
Solve the fol...
Question
Solve the following system of equations by matrix method:
(i) x + y − z = 3
2x + 3y + z = 10
3x − y − 7z = 1
(ii) x + y + z = 3
2x − y + z = − 1
2x + y − 3z = − 9
(iii) 6x − 12y + 25z = 4
4x + 15y − 20z = 3
2x + 18y + 15z = 10
(iv) 3x + 4y + 7z = 14
2x − y + 3z = 4
x + 2y − 3z = 0
(v)
2
x
-
3
y
+
3
z
=
10
1
x
+
1
y
+
1
z
=
10
3
x
-
1
y
+
2
z
=
13
(vi) 5x + 3y + z = 16
2x + y + 3z = 19
x + 2y + 4z = 25
(vii) 3x + 4y + 2z = 8
2y − 3z = 3
x − 2y + 6z = −2
(viii) 2x + y + z = 2
x + 3y − z = 5
3x + y − 2z = 6
(ix) 2x + 6y = 2
3x − z = −8
2x − y + z = −3
(x) x − y + z = 2
2x − y = 0
2y − z = 1
(xi) 8x + 4y + 3z = 18
2x + y +z = 5
x + 2y + z = 5
(xii) x + y + z = 6
x + 2z = 7
3x + y + z = 12
(xiii)
2
x
+
3
y
+
10
z
=
4
,
4
x
-
6
y
+
5
z
=
1
,
6
x
+
9
y
-
20
z
=
2
;
x
,
y
,
z
≠
0
Open in App
Solution
(i)
Here,
A
=
1
1
-
1
2
3
1
3
-
1
-
7
A
=
1
1
-
1
2
3
1
3
-
1
-
7
=
1
-
21
+
1
-
1
-
14
-
3
-
1
(
-
2
-
9
)
=
-
20
+
17
+
11
=
8
Let C
i
j
be the cofactors of the elements a
i
j
in A
a
i
j
. Then,
C
11
=
-
1
1
+
1
3
1
-
1
-
7
=
-
20
,
C
12
=
-
1
1
+
2
2
1
3
-
7
=
17
,
C
13
=
-
1
1
+
3
2
3
3
-
1
=
-
11
C
21
=
-
1
2
+
1
1
-
1
-
1
-
7
=
8
,
C
22
=
-
1
2
+
2
1
-
1
3
-
7
=
-
4
,
C
23
=
-
1
2
+
3
1
1
3
-
1
=
4
C
31
=
-
1
3
+
1
1
-
1
3
1
=
4
,
C
32
=
-
1
3
+
2
1
-
1
2
1
=
-
3
,
C
33
=
-
1
3
+
3
1
1
2
3
=
1
adj
A
=
-
20
17
-
11
8
-
4
4
4
-
3
1
T
=
-
20
8
4
17
-
4
-
3
-
11
4
1
⇒
A
-
1
=
1
A
a
d
j
A
=
1
8
-
20
8
4
17
-
4
-
3
-
11
4
1
X
=
A
-
1
B
⇒
x
y
z
=
1
8
-
20
8
4
17
-
4
-
3
-
11
4
1
3
10
1
⇒
x
y
z
=
1
8
-
60
+
80
+
4
51
-
40
-
3
-
33
+
40
+
1
⇒
x
y
z
=
1
8
24
8
8
⇒
x
=
24
8
,
y
=
8
8
and
z
=
8
8
∴
x
=
3
,
y
=
1
and
z
=
1
(ii)
Here,
A
=
1
1
1
2
-
1
1
2
1
-
3
A
=
1
1
1
2
-
1
1
2
1
-
3
=
1
3
-
1
-
1
-
6
-
2
+
1
(
2
+
2
)
=
2
+
8
+
4
=
14
Let C
i
j
be the cofactors of the elements a
i
j
in A
a
i
j
. Then,
C
11
=
-
1
1
+
1
-
1
1
1
-
3
=
2
,
C
12
=
-
1
1
+
2
2
1
2
-
3
=
8
,
C
13
=
-
1
1
+
3
2
-
1
2
1
=
4
C
21
=
-
1
2
+
1
1
1
1
-
3
=
4
,
C
22
=
-
1
2
+
2
1
1
2
-
3
=
-
5
,
C
23
=
-
1
2
+
3
1
1
2
1
=
1
C
31
=
-
1
3
+
1
1
1
-
1
1
=
2
,
C
32
=
-
1
3
+
2
1
1
2
1
=
1
,
C
33
=
-
1
3
+
3
1
1
2
-
1
=
-
3
adj
A
=
2
8
4
4
-
5
1
2
1
-
3
T
=
2
4
2
8
-
5
1
4
1
-
3
⇒
A
-
1
=
1
A
adj
A
=
1
14
2
4
2
8
-
5
1
4
1
-
3
X
=
A
-
1
B
⇒
x
y
z
=
1
14
2
4
2
8
-
5
1
4
1
-
3
3
-
1
-
9
⇒
x
y
z
=
1
14
6
-
4
-
18
24
+
5
-
9
12
-
1
+
27
⇒
x
y
z
=
1
14
-
16
20
38
⇒
x
=
-
16
14
,
y
=
20
14
and
z
=
38
14
∴
x
=
-
8
7
,
y
=
10
7
and
z
=
19
7
(iii)
Here,
A
=
6
-
12
25
4
15
-
20
2
18
15
A
=
6
-
12
25
4
15
-
20
2
18
15
=
6
225
+
360
+
12
60
+
40
+
25
(
72
-
30
)
=
3510
+
1200
+
1050
=
5760
Let C
i
j
be the cofactors of the elements a
i
j
in A
a
i
j
. Then,
C
11
=
-
1
1
+
1
15
-
20
18
15
=
585
,
C
12
=
-
1
1
+
2
4
-
20
2
15
=
-
100
,
C
13
=
-
1
1
+
3
4
15
2
18
=
42
C
21
=
-
1
2
+
1
-
12
25
18
15
=
630
,
C
22
=
-
1
2
+
2
6
25
2
15
=
40
,
C
23
=
-
1
2
+
3
6
-
12
2
18
=
-
132
C
31
=
-
1
3
+
1
-
12
25
15
-
20
=
-
135
,
C
32
=
-
1
3
+
2
6
25
4
-
20
=
220
,
C
33
=
-
1
3
+
3
6
-
12
4
15
=
138
adj
A
=
585
-
100
42
630
40
-
132
-
135
220
138
T
=
585
630
-
135
-
100
40
220
42
-
132
138
⇒
A
-
1
=
1
A
adj
A
=
1
5760
585
630
-
135
-
100
40
220
42
-
132
138
X
=
A
-
1
B
⇒
x
y
z
=
1
5760
585
630
-
135
-
100
40
220
42
-
132
138
4
3
10
⇒
x
y
z
=
1
5760
2340
+
1890
-
1350
-
400
+
120
+
2200
168
-
396
+
1380
⇒
x
y
z
=
1
5760
2880
1920
1152
⇒
x
=
2880
5760
,
y
=
1920
5760
and
z
=
1152
5760
∴
x
=
1
2
,
y
=
1
3
and
z
=
1
5
(iv)
Here,
A
=
3
4
7
2
-
1
3
2
1
-
3
A
=
3
4
7
2
-
1
3
2
1
-
3
=
3
3
-
3
-
4
-
6
-
6
+
7
(
2
+
2
)
=
0
+
48
+
28
=
76
Let C
i
j
be the cofactors of elements a
i
j
in A
a
i
j
. Then,
C
11
=
-
1
1
+
1
-
1
3
1
-
3
=
0
,
C
12
=
-
1
1
+
2
2
3
2
-
3
=
12
,
C
13
=
-
1
1
+
3
2
-
1
2
1
=
4
C
21
=
-
1
2
+
1
4
7
1
-
3
=
19
,
C
22
=
-
1
2
+
2
3
7
2
-
3
=
-
23
,
C
23
=
-
1
2
+
3
3
4
2
1
=
5
C
31
=
-
1
3
+
1
4
7
-
1
3
=
19
,
C
32
=
-
1
3
+
2
3
7
2
3
=
5
,
C
33
=
-
1
3
+
3
3
4
2
-
1
=
-
11
adj
A
=
0
12
4
19
-
23
5
19
5
-
11
T
=
0
19
19
12
-
23
5
4
5
-
11
⇒
A
-
1
=
1
A
adj
A
=
1
76
0
19
19
12
-
23
5
4
5
-
11
X
=
A
-
1
B
⇒
x
y
z
=
1
76
0
19
19
12
-
23
5
4
5
-
11
14
4
0
⇒
x
y
z
=
1
76
0
+
76
+
0
168
-
92
+
0
56
+
20
+
0
⇒
x
y
z
=
1
76
76
76
76
⇒
x
=
76
76
,
y
=
76
76
and
z
=
76
76
∴
x
=
1
,
y
=
1
and
z
=
1
(v)
Let
1
x
be
a
,
1
y
be
b
and
1
z
be
c.
Here,
A
=
2
-
3
3
1
1
1
3
-
1
2
A
=
2
-
3
3
1
1
1
3
-
1
2
=
2
2
+
1
+
3
2
-
3
+
3
(
-
1
-
3
)
=
6
-
3
-
12
=
-
9
Let C
i
j
be the cofactors of the elements a
i
j
in A
a
i
j
. Then,
C
11
=
-
1
1
+
1
1
1
-
1
2
=
3
,
C
12
=
-
1
1
+
2
1
1
3
2
=
1
,
C
13
=
-
1
1
+
3
1
1
3
-
1
=
-
4
C
21
=
-
1
2
+
1
-
3
3
-
1
2
=
3
,
C
22
=
-
1
2
+
2
2
3
3
2
=
-
5
,
C
23
=
-
1
2
+
3
2
-
3
3
-
1
=
-
7
C
31
=
-
1
3
+
1
-
3
3
1
1
=
-
6
,
C
32
=
-
1
3
+
2
2
3
1
1
=
1
,
C
33
=
-
1
3
+
3
2
-
3
1
1
=
5
adj
A
=
3
1
-
4
3
-
5
-
7
-
6
1
5
T
=
3
3
-
6
1
-
5
1
-
4
-
7
5
⇒
A
-
1
=
1
A
adj
A
=
1
-
9
3
3
-
6
1
-
5
1
-
4
-
7
5
X
=
A
-
1
B
⇒
a
b
c
=
1
-
9
3
3
-
6
1
-
5
1
-
4
-
7
5
10
10
13
⇒
a
b
c
=
1
-
9
30
+
30
-
78
10
-
50
+
13
-
40
-
70
+
65
⇒
a
b
c
=
1
-
9
-
18
-
27
-
45
⇒
x
=
1
a
=
-
9
-
18
,
y
=
1
b
=
-
9
-
27
and
z
=
1
c
=
-
9
-
45
∴
x
=
1
a
=
1
2
,
y
=
1
b
=
1
3
and
z
=
1
c
=
1
5
(vi)
Here,
A
=
5
3
1
2
1
3
1
2
4
A
=
5
3
1
2
1
3
1
2
4
=
5
4
-
6
-
3
8
-
3
+
1
(
4
-
1
)
=
-
10
-
15
+
3
=
-
22
Let C
i
j
be the cofactors of the elements a
i
j
in A
a
i
j
. Then,
C
11
=
-
1
1
+
1
1
3
2
4
=
-
2
,
C
12
=
-
1
1
+
2
2
3
1
4
=
-
5
,
C
13
=
-
1
1
+
3
2
1
1
2
=
3
C
21
=
-
1
2
+
1
3
1
2
4
=
-
10
,
C
22
=
-
1
2
+
2
5
1
1
4
=
19
,
C
23
=
-
1
2
+
3
5
3
1
2
=
-
7
C
31
=
-
1
3
+
1
3
1
1
3
=
8
,
C
32
=
-
1
3
+
2
5
1
2
3
=
-
13
,
C
33
=
-
1
3
+
3
5
3
2
1
=
-
1
adj
A
=
-
2
-
5
3
-
10
19
-
7
8
-
13
-
1
T
=
-
2
-
10
8
-
5
19
-
13
3
-
7
-
1
⇒
A
-
1
=
1
A
adj
A
=
1
-
22
-
2
-
10
8
-
5
19
-
13
3
-
7
-
1
X
=
A
-
1
B
⇒
x
y
z
=
1
-
22
-
2
-
10
8
-
5
19
-
13
3
-
7
-
1
16
19
25
⇒
x
y
z
=
1
-
22
-
32
-
190
+
200
-
80
+
361
-
325
48
-
133
-
25
⇒
x
y
z
=
1
-
22
-
22
-
44
-
110
⇒
x
=
-
22
-
22
,
y
=
-
44
-
22
and
z
=
-
110
-
22
∴
x
=
1
,
y
=
2
and
z
=
5
(vii)
Here,
A
=
3
4
2
0
2
-
3
1
-
2
6
A
=
3
4
2
0
2
-
3
1
-
2
6
=
3
12
-
6
-
4
0
+
3
+
2
(
0
-
2
)
=
18
-
12
-
4
=
2
Let C
i
j
be the cofactors of the elements a
i
j
in A
a
i
j
. Then,
C
11
=
-
1
1
+
1
2
-
3
-
2
6
=
6
,
C
12
=
-
1
1
+
2
0
-
3
1
6
=
-
3
,
C
13
=
-
1
1
+
3
0
2
1
-
2
=
-
2
C
21
=
-
1
2
+
1
4
2
-
2
6
=
-
28
,
C
22
=
-
1
2
+
2
3
2
1
6
=
16
,
C
23
=
-
1
2
+
3
3
4
1
-
2
=
10
C
31
=
-
1
3
+
1
4
2
2
-
3
=
-
16
,
C
32
=
-
1
3
+
2
3
2
0
-
3
=
9
,
C
33
=
-
1
3
+
3
3
4
0
2
=
6
adj
A
=
6
-
3
-
2
-
28
16
10
-
16
9
6
T
=
6
-
28
-
16
-
3
16
9
-
2
10
6
⇒
A
-
1
=
1
A
adj
A
=
1
2
6
-
28
-
16
-
3
16
9
-
2
10
6
X
=
A
-
1
B
⇒
x
y
z
=
1
2
6
-
28
-
16
-
3
16
9
-
2
10
6
8
3
-
2
⇒
x
y
z
=
1
2
48
-
84
+
32
-
24
+
48
-
18
-
16
+
30
-
12
⇒
x
y
z
=
1
2
-
4
6
2
⇒
x
=
-
4
2
,
y
=
6
2
and
z
=
2
2
∴
x
=
-
2
,
y
=
3
and
z
=
1
(
viiii
)
Here
,
A
=
2
1
1
1
3
-
1
3
1
-
2
A
=
2
1
1
1
3
-
1
3
1
-
2
=
2
-
6
+
1
-
1
-
2
+
3
+
1
(
1
-
9
)
=
-
10
-
1
-
8
=
-
19
Let C
i
j
be the cofactors of the elements a
i
j
in A
a
i
j
. Then,
C
11
=
-
1
1
+
1
3
-
1
1
-
2
=
-
5
,
C
12
=
-
1
1
+
2
1
-
1
3
-
2
=
-
1
,
C
13
=
-
1
1
+
3
1
3
3
1
=
-
8
C
21
=
-
1
2
+
1
1
1
1
-
2
=
3
,
C
22
=
-
1
2
+
2
2
-
1
3
-
2
=
-
7
,
C
23
=
-
1
2
+
3
2
1
3
1
=
1
C
31
=
-
1
3
+
1
1
1
3
-
1
=
-
4
,
C
32
=
-
1
3
+
2
2
1
1
-
1
=
3
,
C
33
=
-
1
3
+
3
2
1
1
3
=
5
adj
A
=
-
5
-
1
-
8
3
-
7
1
-
4
3
5
T
=
-
5
3
-
4
-
1
-
7
3
-
8
1
5
⇒
A
-
1
=
1
A
adj
A
=
1
-
19
-
5
3
-
4
-
1
-
7
3
-
8
1
5
X
=
A
-
1
B
⇒
x
y
z
=
1
-
19
-
5
3
-
4
-
1
-
7
3
-
8
1
5
2
5
6
⇒
x
y
z
=
1
-
19
-
10
+
15
-
24
-
2
-
35
+
18
-
16
+
5
+
30
⇒
x
y
z
=
1
-
19
-
19
19
19
⇒
x
=
-
19
-
19
,
y
=
19
-
19
and
z
=
19
-
19
∴
x
=
1
,
y
=
3
and
z
=
-
1
(
ix
)
Here
,
A
=
2
6
0
3
0
-
1
2
-
1
1
A
=
2
6
0
3
0
-
1
2
-
1
1
=
2
0
-
1
-
6
3
+
2
+
0
(
-
3
+
0
)
=
-
2
-
30
=
-
32
Let C
i
j
be the cofactors of the elements a
i
j
in A
a
i
j
. Then,
C
11
=
-
1
1
+
1
0
-
1
-
1
1
=
-
1
,
C
12
=
-
1
1
+
2
3
-
1
2
1
=
-
5
,
C
13
=
-
1
1
+
3
3
0
2
-
1
=
-
3
C
21
=
-
1
2
+
1
6
0
-
1
1
=
-
6
,
C
22
=
-
1
2
+
2
2
0
2
1
=
2
,
C
23
=
-
1
2
+
3
2
6
2
-
1
=
14
C
31
=
-
1
3
+
1
6
0
0
-
1
=
-
6
,
C
32
=
-
1
3
+
2
2
0
3
-
1
=
2
,
C
33
=
-
1
3
+
3
2
6
3
0
=
-
18
adj
A
=
-
1
-
5
-
3
-
6
2
14
-
6
2
-
18
T
=
-
1
-
6
-
6
-
5
2
2
-
3
14
-
18
⇒
A
-
1
=
1
A
adj
A
=
1
-
32
-
1
-
6
-
6
-
5
2
2
-
3
14
-
18
X
=
A
-
1
B
⇒
x
y
z
=
1
-
32
-
1
-
6
-
6
-
5
2
2
-
3
14
-
18
2
-
8
-
3
⇒
x
y
z
=
1
-
32
-
2
+
48
+
18
-
10
-
16
-
6
-
6
-
112
+
54
⇒
x
y
z
=
1
-
32
64
-
32
-
64
⇒
x
=
64
-
32
,
y
=
-
32
-
32
and
z
=
-
64
-
32
∴
x
=
-
2
,
y
=
1
and
z
=
2
(
x
)
Here
,
A
=
1
-
1
1
2
-
1
0
0
2
-
1
A
=
1
-
1
1
2
-
1
0
0
2
-
1
=
1
1
-
0
+
1
-
2
-
0
+
1
(
4
-
0
)
=
1
-
2
+
4
=
3
Let C
i
j
be the cofactors of the elements a
i
j
in A
a
i
j
. Then,
C
11
=
-
1
1
+
1
-
1
0
2
-
1
=
1
,
C
12
=
-
1
1
+
2
2
0
0
-
1
=
2
,
C
13
=
-
1
1
+
3
2
-
1
0
2
=
4
C
21
=
-
1
2
+
1
-
1
1
2
-
1
=
1
,
C
22
=
-
1
2
+
2
1
1
0
-
1
=
-
1
,
C
23
=
-
1
2
+
3
1
-
1
0
2
=
-
2
C
31
=
-
1
3
+
1
-
1
1
-
1
0
=
1
,
C
32
=
-
1
3
+
2
1
1
2
0
=
2
,
C
33
=
-
1
3
+
3
1
-
1
2
-
1
=
1
adj
A
=
1
2
4
1
-
1
-
2
1
2
1
T
=
1
1
1
2
-
1
2
4
-
2
1
⇒
A
-
1
=
1
A
adj
A
=
1
1
1
1
1
2
-
1
2
4
-
2
1
X
=
A
-
1
B
⇒
x
y
z
=
1
3
1
1
1
2
-
1
2
4
-
2
1
2
0
1
⇒
x
y
z
=
1
3
2
+
1
4
+
2
8
+
1
⇒
x
y
z
=
1
1
3
6
9
⇒
x
=
3
3
,
y
=
6
3
and
z
=
9
3
∴
x
=
1
,
y
=
2
and
z
=
3
(
xi
)
Here
,
A
=
8
4
3
2
1
1
1
2
1
A
=
8
4
3
2
1
1
1
2
1
=
8
1
-
2
-
4
2
-
1
+
3
(
4
-
1
)
=
-
8
-
4
+
9
=
-
3
Let C
i
j
be the cofactors of the elements a
i
j
in A
a
i
j
. Then,
C
11
=
-
1
1
+
1
1
1
2
1
=
-
1
,
C
12
=
-
1
1
+
2
2
1
1
1
=
-
1
,
C
13
=
-
1
1
+
3
2
1
1
2
=
3
C
21
=
-
1
2
+
1
4
3
2
1
=
2
,
C
22
=
-
1
2
+
2
8
3
1
1
=
5
,
C
23
=
-
1
2
+
3
8
4
1
2
=
-
12
C
31
=
-
1
3
+
1
4
3
1
1
=
1
,
C
32
=
-
1
3
+
2
8
3
2
1
=
-
2
,
C
33
=
-
1
3
+
3
8
4
2
1
=
0
adj
A
=
-
1
-
1
3
2
5
-
12
1
-
2
0
T
=
-
1
2
1
-
1
5
-
2
3
-
12
0
⇒
A
-
1
=
1
A
adj
A
=
1
-
3
-
1
2
1
-
1
5
-
2
3
-
12
0
X
=
A
-
1
B
⇒
x
y
z
=
1
-
3
-
1
2
1
-
1
5
-
2
3
-
12
0
18
5
5
⇒
x
y
z
=
1
-
3
-
18
+
10
+
5
-
18
+
25
-
10
54
-
60
⇒
x
y
z
=
1
-
3
-
3
-
3
-
6
⇒
x
=
-
3
-
3
,
y
=
-
3
-
3
and
z
=
-
6
-
3
∴
x
=
1
,
y
=
1
and
z
=
2
(
xii
)
Here
,
A
=
1
1
1
1
0
2
3
1
1
A
=
1
1
1
1
0
2
3
1
1
=
1
0
-
2
-
1
1
-
6
+
1
(
1
-
0
)
=
-
2
+
5
+
1
=
4
Let C
i
j
be the cofactors of the elements a
i
j
in A
a
i
j
. Then,
C
11
=
-
1
1
+
1
0
2
1
1
=
-
2
,
C
12
=
-
1
1
+
2
1
2
3
1
=
5
,
C
13
=
-
1
1
+
3
1
0
3
1
=
1
C
21
=
-
1
2
+
1
1
1
1
1
=
0
,
C
22
=
-
1
2
+
2
1
1
3
1
=
-
2
,
C
23
=
-
1
2
+
3
1
1
3
1
=
2
C
31
=
-
1
3
+
1
1
1
0
2
=
2
,
C
32
=
-
1
3
+
2
1
1
1
2
=
-
1
,
C
33
=
-
1
3
+
3
1
1
1
0
=
-
1
adj
A
=
-
2
5
1
0
-
2
2
2
-
1
-
1
T
=
-
2
0
2
5
-
2
-
1
1
2
-
1
⇒
A
-
1
=
1
A
adj
A
=
1
4
-
2
0
2
5
-
2
-
1
1
2
-
1
X
=
A
-
1
B
⇒
x
y
z
=
1
4
-
2
0
2
5
-
2
-
1
1
2
-
1
6
7
12
⇒
x
y
z
=
1
4
-
12
+
0
+
24
30
-
14
-
12
6
-
14
-
12
⇒
x
y
z
=
1
4
12
4
-
20
⇒
x
=
12
4
,
y
=
4
4
and
z
=
-
20
4
∴
x
=
3
,
y
=
1
and
z
=
-
5
(xiii)
Let
1
x
be
a,
1
y
be
b
and
1
z
be
c.
Here,
A
=
2
3
10
4
-
6
5
6
9
-
20
A
=
2
3
10
4
-
6
5
6
9
-
20
=
2
120
-
45
-
3
-
80
-
30
+
10
(
36
+
36
)
=
150
+
330
+
720
=
1200
Let C
i
j
be the cofactors of the elements a
i
j
in A
a
i
j
. Then,
C
11
=
-
1
1
+
1
-
6
5
9
-
20
=
75
,
C
12
=
-
1
1
+
2
4
5
6
-
20
=
110
,
C
13
=
-
1
1
+
3
4
-
6
6
9
=
72
C
21
=
-
1
2
+
1
3
10
9
-
20
=
150
,
C
22
=
-
1
2
+
2
2
10
6
-
20
=
-
100
,
C
23
=
-
1
2
+
3
2
3
6
9
=
0
C
31
=
-
1
3
+
1
3
10
-
6
5
=
75
,
C
32
=
-
1
3
+
2
2
10
4
5
=
30
,
C
33
=
-
1
3
+
3
2
3
4
-
6
=
-
24
adj
A
=
75
110
72
150
-
100
0
75
30
-
24
T
=
75
150
75
110
-
100
30
72
0
-
24
⇒
A
-
1
=
1
A
adj
A
=
1
1200
75
150
75
110
-
100
30
72
0
-
24
X
=
A
-
1
B
⇒
a
b
c
=
1
1200
75
150
75
110
-
100
30
72
0
-
24
4
1
2
⇒
a
b
c
=
1
1200
300
+
150
+
150
440
-
100
+
60
288
-
48
⇒
a
b
c
=
1
1200
600
400
240
⇒
x
=
1
a
=
1200
600
,
y
=
1
b
=
1200
400
and
z
=
1
c
=
1200
240
∴
x
=
2
,
y
=
3
and
z
=
5
Suggest Corrections
0
Similar questions
Q.
Solve by matrix method:
2
x
+
3
y
+
3
z
=
5
x
−
2
y
+
z
=
−
4
3
x
−
y
−
2
z
=
3
Q.
3x − y + 2z = 3
2x + y + 3z = 5
x − 2y − z = 1
Q.
Solve:-
x
−
2
y
+
3
z
=
11
3
x
+
y
−
z
=
2
5
x
+
3
y
+
2
z
=
3
Q.
Show that each of the following systems of linear equations is consistent and also find their solutions:
(i) 6x + 4y = 2
9x + 6y = 3
(ii) 2x + 3y = 5
6x + 9y = 15
(iii) 5x + 3y + 7z = 4
3x + 26y + 2z = 9
7x + 2y + 10z = 5
(iv) x − y + z = 3
2x + y − z = 2
−x −2y + 2z = 1
(v) x + y + z = 6
x + 2y + 3z = 14
x + 4y + 7z = 30
(vi) 2x + 2y − 2z = 1
4x + 4y − z = 2
6x + 6y + 2z = 3
Q.
Solve the system of equations, using matrix method
2
x
+
3
y
+
3
z
=
5
,
x
−
2
y
+
z
=
−
4
,
3
x
−
y
−
2
z
=
3
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