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Question

Solve the following system of equations by the elimination method and the substitution method:

x=2y+57y=2x-7


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Solution

Elimination method

Step(1): Making coefficient of variable(xory)equal

Multiply the given equation needed by a suitable number so that the coefficient of one of the variables says (xory)become equal.

Multiply by 2 in x=2y+5

2x=4y+107y=2x-7

i.e. -2x=-7y-7......................................................(1)

Step (2):Eliminating the variable x

Add the equation obtained in step-(1)to eliminate one variable. The resulting equation is a linear equation in one variable.

0=-3y+3................................................(2).

-3=-3yy=33y=1

Step (3): Obtain value of other variable

Substitute this value of y=1 to the variable in either of the original equations, to get the value of the other variable.

x=2y+5x=(2×1)+5x=2+5x=7

Substitution Method

Step(1): Express one variable in terms of other

Express one variable (sayx) in terms of other variable (sayy) from one of the given equations.

x=2y+5........................................(1)

Step (2): Use the second equation

Substitute this value of x=2y+5 in the other equations to get a linear equations in y which can be solved.

7y=2x-7....................................................(2)7y=2(2y+5)-77y=4y+10-77y-4y=33y=3y=1

Step (3) : Finding the other variable.

Substitute the values of y obtained in step-(2) above in the equations used in step- (1)to get the values of x.

x=2y+5x=(2×1)+5x=2+5x=7

Hence,by both mehod answer is same and x=7, y=1


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