Question

Solve the following system of equations using elimination method:​
$2x+7y=10$​
$3x+y=6$

• A. $\frac{32}{19},\frac{18}{19}$
• B. $\frac{-3}{5},\frac{9}{5}$
• C. $\frac{11}{25},\frac{9}{25}$
• D. $\frac{12}{19},\frac{-1}{19}$

Answer 1

The correct option is A $\frac{32}{19},\frac{18}{19}$

We have equations,​

$2x+7y=10$ …………………………. (i)​

$3x+y=6$ ………………………….. (ii)​

​Multiply equation (ii) with 7 to make one of the coefficient same,​

$21x+7y=42$ ………………………….. (iii)​

Subtract (i) from (iii)​
$19x=32$​
$x=\frac{32}{19}$​

Substitute x in any of the equation to get y.​

$2\times \frac{32}{19}+7y=10$​

$7y=\frac{126}{19}$​

$y=\frac{18}{19}$