Solve the following system of linear equations.
$x + 2 y - 4 = 0$
$2 x + 4 y - 12 = 0$

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Solution

Given, the equations
$x + 2 y - 4 = 0$ .......(1)
And
$2 x + 4 y - 12 = 0$
or, $x + 2 y = 6$ .....(2).
There is no solution for the given system as it is impossible to have solutions $x, y$ such that $x + 2 y = 4$ and $x + 2 y = 6$ . As (1) and (2) are same equations with different constant terms.

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