Question

Solve the following systems of equations:
$\frac{4}{x}+3y=14$
$\frac{3}{x}-4y=23$

Answer 1

Equation (1)×3 : $\frac{12}{x}+9y=42$

Equation (2)×4 : $\frac{12}{x}-16y=92$

Subtract two equations ;

$\Rightarrow 25y=-50$

$\Rightarrow y=-2$

Substituting 'y' in equation (1),we get ;

$\Rightarrow x=\frac{1}{5}$