Question

Solve the following systems of equations:
$\frac{4}{x}+3y=8$
$\frac{6}{x}-4y=-5$

Answer 1

Equation (1) ×4 : $\frac{16}{x}+12y=32$

Equation (2)×3 : $\frac{18}{x}-12y=-15$

Add two equations ;

$\Rightarrow \frac{34}{x}=17$

$\Rightarrow x=2$

Substitute x in equation (2);

$\Rightarrow y=2$