Question

Solve the following systems of equations graphically:
$3x+y+1=0$
$2x-3y+8=0$

Answer 1

Given: equations of two lines: $3x+y+1=0$ and $2x-3y+8=0$

(1) Intercept of line $3x+y+1=0$

at $x=0,y=-1$

at $y=0,x=\frac{-1}{3}$

Now plot the first line on the graph using intercepts.

(2) Intercepts of the line $2x-3y+8=0$

at $x=0,y=\frac{8}{3}$

at $y=0,x=-4$

Now plot the second line on the graph using intercepts.

We can see that these two lines intersect a point $x=-1,y=2$