Question

Solve the following
Find the roots of quadratic equation $2x^2-4x+3=0$ by completing the square find the roots of quadratic equation by using the formula

Answer 1

$2x^2-4x+3=0$

Roots are $\frac{4\pm \sqrt{16-4\left(3\right)\left(2\right)}}{2x^2}$

$=\frac{4\pm \sqrt{16-24}}{4}=\frac{4\pm \sqrt{-8}}{4}$

$=\frac{4\pm 2\sqrt{2}i}{4}$

$=\frac{2\pm \sqrt{2}i}{2}$

Roots are $\frac{2+\sqrt{2}i}{2},\frac{2-\sqrt{2}i}{2}$