Solve the given pair of equations by substitution method:
$x - 4 y = - 8$
$x - 2 y = 0$

(2, - 1)

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(7, - 6)

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(8, 4)

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(- 3, 6)

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Solution

The correct option is C $(8, 4)$
We have, $x - 4 y = - 8 \Rightarrow x = 4 y - 8$ ..........(1)
and $x - 2 y = 0$ .......(2)
Now substitute value of x in terms of y from (1) to (2)
$\Rightarrow 4 y - 8 - 2 y = 0$
$\Rightarrow 2 y = 8$
$\Rightarrow y = \frac{8}{2} = 4$
So $x = 4 y - 8 = 4 (4) - 8 = 8$
Hence solution set is $(x, y) = (8, 4)$

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