Question

Solve the inequality: $3-2x\le 9$

• A. $x\le 8$
• B. $x\ge -6$
• C. $x\le -3$
• D. $x\ge -3$

Answer 1

The correct option is D $x\ge -3$

$3-2x\le 9$

Add -3 both sides we get

$3-2x-3\le 9-3$

$\Rightarrow -2x\le 6$

Divided by -2 both sides we get

$x\ge -3$