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Question
Solve the inequality 3(x−1)≤2(x−3) for real x
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Solution
3(x−1)≤2(x−3)
⇒3x−3≤2x−6
⇒3x−3−2x+6≤0
⇒x+3≤0
⇒x≤−3
∴x∈(−∞,−3]
3(x−1)≤2(x−3)
⇒3x−3≤2x−6
⇒3x−3−2x+6≤0
⇒x+3≤0
⇒x≤−3
∴x∈(−∞,−3]
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